This experiment determines the refractive index of water by shining a narrow laser beam vertically onto a shallow dish of water and measuring the diameter of the circular light ring formed due to total internal reflection at the water-air interface.
When a laser beam enters water vertically, light rays hitting the water-air interface at an angle greater than the critical angle undergo total internal reflection. The result is a **circular light ring observed at the bottom or projected on a screen.
If the depth of water is \( h \) and the radius of the ring formed is \( r \), then the refractive index \( \mu \) is given by:
\[ \mu = \frac{r}{\sqrt{4h^2 + r^2}}\]
This formula comes from trigonometry, using the relationship between the critical angle \( \theta_c \) and the dimensions of the light path:
\[ \sin \theta_c = \frac{h}{\sqrt{h^2 + (r/2)^2}} \quad , \quad \mu = \frac{1}{\sin \theta_c} \]
Record the following:
Using the measured values:
\[ \mu = \frac{r}{\sqrt{4h^2 + r^2}}\]
Take multiple readings for accuracy and calculate the mean refractive index:
\[ \mu_\text{mean} = \frac{\mu_1 + \mu_2 + \mu_3 + \dots}{n} \]
The refractive index of water is obtained using the measured ring radius and water depth, confirming the refraction properties of water and total internal reflection.
Video courtesy of Turbulent Tech World (YouTube). Used for educational purposes under YouTube’s embedding policy.